Example 2: When 245 grams of potassium chlorate are heated, the potassium chlorate breaks down into 78 grams of potassium, 71 grams of chlorine and some oxygen gas. Find out the mass of oxygen gas formed.

Write the word equation Potassium chlorate → potassium + chlorine + oxygen
Place the masses of the given substance below the equation           245g                78g             71g         ???
Apply the law of conservation of mass 245 = 78 + 71 + ?
Solve for the missing mass 245 = 149 + ? 245 - 149 = ? ? = 96

Answer: 96g of oxygen were formed.



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